Minersville, UT Real Estate

Minersville is a town in Beaver County, Utah, United States. The population was 817 at the 2000 census.

Minersville is located at 38 °12 48 N, 112 °55 30 W (38.213242, -112.924928) GR1.

According to the United States Census Bureau, the town has a total area of 1.6 km (0.6 mi ), all land.

As of the census GR2 of 2000, there were 817 people, 256 households, and 204 families residing in the town. The population density was 500.7/km (1,289.3/mi ). There were 274 housing units at an average density of 167.9/km (432.4/mi ). The racial makeup of the town was 93.76% White, 0.12% Asian, 0.12% Pacific Islander, 4.16% from other races, and 1.84% from two or more races. Hispanic or Latino of any race were 6.00% of the population.

There were 256 households out of which 49.2% had children under the age of 18 living with them, 73.0% were married couples living together, 5.1% had a female householder with no husband present, and 20.3% were non-families. 18.0% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 3.19 and the average family size was 3.68.

Featured Homes in Minersville, UT

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Price City, State Property Type Beds/Baths Sq.Ft. Miles $79,500 Milford, UT Single Family 2/1 1060 20.6 $229,900 Parowan, UT Single Family 0/0 0 24.3 $239,000 Parowan, UT Single Family 4/2 2600 24.3

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Minersville, UT Neighborhood Info